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if log_(16)25 = k log_(2)5 then k = _____
![Given that lim_(nto oo) sum_(r=1)^(n) (log (r+n)-log n)/(n)=2(log 2-(1)/(2)), lim_(n to oo) (1)/(n^k)[(n+1)^k(n+2)^k.....(n+n)^k]^(1//n), is](https://d10lpgp6xz60nq.cloudfront.net/question-thumbnail/en_53803583.png "Given that lim_(nto oo) sum_(r=1)^(n) (log (r+n)-log n)/(n)=2(log 2-(1)/(2)), lim_(n to oo) (1)/(n^k)[(n+1)^k(n+2)^k.....(n+n)^k]^(1//n), is")
Given that lim_(nto oo) sum_(r=1)^(n) (log (r+n)-log n)/(n)=2(log 2-(1)/(2)), lim_(n to oo) (1)/(n^k)[(n+1)^k(n+2)^k.....(n+n)^k]^(1//n), is
![PDF] The series limit of sum_k 1/[k log k (log log k)^2] | Semantic Scholar](https://d3i71xaburhd42.cloudfront.net/bcb8e5cb03f7bbef7fee346bb29e984b7cef32a4/2-Figure1-1.png "PDF] The series limit of sum_k 1/[k log k (log log k)^2] | Semantic Scholar")
PDF] The series limit of sum_k 1/[k log k (log log k)^2] | Semantic Scholar
What is the fastest way to know K, given N, where n = 2^k? - Quora
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Solutions to Midterm 1. Question 1 Recurrence Relation T(n) = 4T(n/2) + n 2, n 2; T(1) = 1 (a)Height of the recursion tree: Assume n = 2 k height: k. - ppt download
Evaluate the series $S_n = \sum_{k=1}^n\log\frac {k (k + 2)}{(k + 1)^2}$ - Mathematics Stack Exchange
